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0x4E4F@lemmy.fmhy.ml to Memes@lemmy.ml · 3年前

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lemmy.fmhy.ml

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lemmy.fmhy.ml

0x4E4F@lemmy.fmhy.ml to Memes@lemmy.ml · 3年前
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  • s_s
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    3年前

    I bet someone knows an arithmetic topology where this is true.

    • lowleveldata@programming.dev
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      3年前

      Just redefine how you write multiplication

      • CAPSLOCKFTW@lemmy.ml
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        3年前

        Actually, (sorry for that beginning) if we assume that these numbers are elements of the additive group of the integers (ℤ,+), some people define z^n for z∈ℤ and n∈ℕ as z+z+…+z}n-times

    • triarius@programming.dev
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      3年前

      In mod 3 they’re all 0.

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