Wouldn’t that give you 11-100?
l
The Lowest number on a dice is 1, and 1×10 gives you 10.
The formula would have to be
((d10-1)×10)+d10=x≥90⟹y=(y+1)⟹z>1(d2)
So you’d still have to flip a coin on reaching a result of 90+ in order to know if you add a +1 or not as well or else you can’t get 90 as a result either.
(This is assuming you have a d10 that’s 1-10 btw and not 0-9!)
Wouldn’t that give you 11-100? l The Lowest number on a dice is 1, and 1×10 gives you 10.
The formula would have to be
((d10-1)×10)+d10=x≥90⟹y=(y+1)⟹z>1(d2)
So you’d still have to flip a coin on reaching a result of 90+ in order to know if you add a +1 or not as well or else you can’t get 90 as a result either.
(This is assuming you have a d10 that’s 1-10 btw and not 0-9!)
there’s a 0 on the die
to roll 1:
1st, 0 x 10 = 0
2nd, 0+0 = 0
add 1, 0 + 1 = 1
to roll 100:
1st, 9 x 10 = 90
2nd, 90 + 9 = 99
add 1, 99 + 1 = 100