For example, is there any problems with doing this?
fn main() {
static mut BUF: [u8; 0x400] = [0; 0x400];
let buf = &mut unsafe { BUF };
}
and is this code the same as just using an array directly? From my understanding local variables get put on the stack but do the static variables do too?
I’m essentially trying to find the most performant way to get a simple read/write buffer.
My logic was simply: I need a buffer that is only initialised once no matter how many times the function is called. statics are initialised at program start so they seemed like a good fit. and since I wasn’t planning for the function to me called multiple times simultaneously it seemed like the UB didn’t matter. (which I think was correct)
There is no such a thing.
If you really must pretend this matters performance wise, look up
MaybeUninit. It still requiresunsafe{}, but it’s a lot less trouble.