Day 11: Reactor
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Uiua
If it’s stupid but it works…
My dirty hack
I broke the maze into SVR>FFT>DAC>OUT and SVR>DAC>FFT>OUT, realised that the latter was taking a suspiciously long time, so submitted just the answer from the former --> success!
link (You’ll need to up the execution limit)
# AOC2025day11 - mazes. # Uncomment for Part 1 D ← "aaa: you hhh\nyou: bbb ccc\nbbb: ddd eee\nccc: ddd eee fff\nddd: ggg\neee: out\nfff: out\nggg: out\nhhh: ccc fff iii\niii: out" # Uncomment for Part 2 # D ← "svr: aaa bbb\naaa: fft\nfft: ccc\nbbb: tty\ntty: ccc\nccc: ddd eee\nddd: hub\nhub: fff\neee: dac\ndac: fff\nfff: ggg hhh\nggg: out\nhhh: out" # D ← &fras "randomAOC/AOC2025day11.txt" Tabs ← ⊜(⊙□°⊂⊜∘¬⊸∊": ")⊸≠@\nD Nexts ← ⍣(°□⊡˜⨂⊙Tabs|[]) Part₁ ← ⊙◌⧻path(˙≠°⊏Nexts|≍"out")"you" Part₂ ← ( ⊙◌⧻path(˙≠°⊏Nexts|≍"fft")"svr" ⊙◌⧻path(˙≠°⊏Nexts|≍"dac")"fft" ⊙◌⧻path(˙≠°⊏Nexts|≍"out")"dac" ×× ) # Only one will be right for the test data, depending on dataset. ⊃Part₁ Part₂I also broke up the pathing, mine has zero paths from DAC to FFT. If I join DAC directly FFT, i get a stackoverflow, so maybe its intentional.
If you can explain why it works, not calculating half the paths isn’t a hack—it’s an optimization. ;)
I think the hack was just skipping the entire second set of paths, but yeah, splitting was an nice optimisation. Might not scale as well if that path had to hit multiple intermediate nodes though.
Yes, it felt a little more like I was solving the puzzle-setter rather than the puzzle today.