assume your hypothetical sheet of paper has thickness 1u;
on fold iteration 1: thickness of the paper is doubled, 21u = 2u
on fold iteration 2: thickness gets doubled again l, 22u = 4u
this pattern continues for all subsequent iteration and by the seventh iteration the thickness of the paper is
27 * 1u = 128u
hence by the seventh iteration, assuming you have managed to reach this far, you will be trying to fold something that is 128 times thicker than your first fold.
also whether it be DIN A4 or DIN A1 it doesnt matter, the ability to fold is dependent on the thickness of the paper, which is the same.
“Urine is sterile”
“You can only fold paper 7 times”
Etc.
The paper thing is is testable! It’s not wrong. «You» can’t do it
Did it yesterday
DIN A4? Maybe
DIN A1? I can do more than 7 times
there’s a mythbuster episode on it https://m.youtube.com/watch?v=l9w8GjMeWGo
So you say butter paper is the trick.
Also I would count the half folded ones too
assume your hypothetical sheet of paper has thickness 1u; on fold iteration 1: thickness of the paper is doubled, 21u = 2u on fold iteration 2: thickness gets doubled again l, 22u = 4u
this pattern continues for all subsequent iteration and by the seventh iteration the thickness of the paper is 27 * 1u = 128u
hence by the seventh iteration, assuming you have managed to reach this far, you will be trying to fold something that is 128 times thicker than your first fold.
also whether it be DIN A4 or DIN A1 it doesnt matter, the ability to fold is dependent on the thickness of the paper, which is the same.
Yes’nt.
You are correct on the thickness. However the folding makes it smaller. And the smaller it gets the less leverage you have.
Oh, no you can’t