Day 7: Camel Cards

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  • cacheson@kbin.social
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    1 year ago

    Nim

    I wrote some nice code for sorting poker hands, just defining the < and == operations for my CardSet and Hand types, and letting the standard library’s sort function handle the rest.

    It was quite frustrating to be told that my answer was wrong, though. I dumped the full sorted hand list and checked it manually to make sure everything was working properly, and it was. Wasted a few hours trying to figure out what was wrong. Ended up grabbing someone else’s code and running it in order to compare the resulting hand list. Theirs was clearly ordered wrong, but somehow ended up with the correct answer?

    Turns out that Camel Cards isn’t Poker. -_-

    Rather than rewrite my code entirely, I settled on some slightly ugly hacks to make it work for Camel Cards, and to handle the wildcards in part 2.

  • mykl@lemmy.world
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    1 year ago

    Dart

    I’m glad I took the time to read the directions very carefully before starting coding :-)

    Top Tip: my ranking of hand types relies on the fact that if you count instances of each face and sort the resulting list from high to low, you get a list that when compared with lists from other hands gives an exact correspondence with the order of the hand types as defined, so no need for a bunch of if/thens, just

      var type = Multiset.from(hand).counts.sorted(descending).join('');
    

    Otherwise it should all be pretty self-explanatory apart from where I chose to map card rank to hex digits in order to facilitate sorting, so ‘b’ means ‘J’!

    int descending(T a, T b) => b.compareTo(a);
    var cToH = "  23456789TJQKA"; // used to map card rank to hex for sorting.
    
    handType(List hand, {wildcard = false}) {
      var type = Multiset.from(hand).counts.sorted(descending).join('');
      var i = hand.indexOf('b');
      return (!wildcard || i == -1)
          ? type
          : '23456789acde'
              .split('')
              .map((e) => handType(hand.toList()..[i] = e, wildcard: true))
              .fold(type, (s, t) => s.compareTo(t) >= 0 ? s : t);
    }
    
    solve(List lines, {wildcard = false}) => lines
        .map((e) {
          var l = e.split(' ');
          var hand =
              l.first.split('').map((e) => cToH.indexOf(e).toRadixString(16));
          var type = handType(hand.toList(), wildcard: wildcard);
          if (wildcard) hand = hand.map((e) => e == 'b' ? '0' : e);
          return (hand.join(), type, int.parse(l.last));
        })
        .sorted((a, b) {
          var c = a.$2.compareTo(b.$2);
          return (c == 0) ? a.$1.compareTo(b.$1) : c;
        })
        .indexed(offset: 1)
        .map((e) => e.value.$3 * e.index)
        .sum;
    
    part1(List lines) => solve(lines);
    
    part2(List lines) => solve(lines, wildcard: true);
    
  • janAkali
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    1 year ago

    Nim

    Part 1 is just a sorting problem. Nim’s standard library supports sorting with custom compare functions, so I only had to implement cmp() for my custom type and I was done in no time.
    To get the star in Part 2 I was generating every possible combination of card hands with Jokers replaced by other cards. It was pretty fast, under a second. Didn’t figure out the deterministic method by myself, but coded it after couple hints from Nim Discord people.
    Didn’t expect an easy challenge for today, but was pleasantly surprised. No weird edge cases, no hidden traps, puzzle text was easy to understand and input parsing is painless.

    Total runtime: 1 ms
    Puzzle rating: Almost Pefect 9/10
    Code: day_07/solution.nim

  • mykl@lemmy.world
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    1 year ago

    It’s Uiua time!

    It works, but even I can’t understand this code any more as I’m well into my second beer, so don’t put this into production, okay? (Run it here if you dare.)

    {"32T3K 765"
     "T55J5 684"
     "KK677 28"
     "KTJJT 220"
     "QQQJA 483"}
    StoInt ← /(10)▽×⊃(0)(9).-@0
    ToHex ← ⊏:"  23456789abcde":"  23456789TJQKA"
    ToHexJ ← ⊏:"  23456789a0cde":"  23456789TJQKA"
    # A hand of "311" with one J will have same rank as "41"
    # Dots indicate impossible hands.
    Rankings ← {
      {"11111" "2111" "221" "311" "32" "41" "5"}   # 0
      {"..." "11111" ".." "2111" "221" "311" "41"} # 1
      {"..." "....." ".." "2111" "..." "221" "32"} # 2
      {"..." "....." ".." "...." "..." "311" "32"} # 3
      {"..." "....." ".." "...." "..." "..." "41"} # 4
      {"..." "....." ".." "...." "..." "..." "5"}  # 5
    }
    RankHand ← (
      +@0⊏⍖.⊕⧻⊛⊢⍉⇌⊕∘⍖...          # Count instances, sort desc, to string
      ⊗⊃⊢(⊔⊡:Rankings/+=@0⊢↘1)⊟∩□ # Use table to get ranking
    )
    ScoreHands!((⊐⊟⊓(⊐⊟RankHand.^1)∘⍘⊟) # Rank every hand
      /+/×⊟+1⇡⧻.∵⊔≡(⊢↘1)⊏⍏≡⊢.   # Sort based on rankings
    )
    ⍉⊟⊓∘(∵StoInt)⍘⊟⍉≡(⊐⊜∘≠@\s.) # Parse input(ScoreHands!ToHex)(ScoreHands!ToHexJ)
    
    
  • cvttsd2si@programming.dev
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    1 year ago

    Scala3

    val tiers = List(List(1, 1, 1, 1, 1), List(1, 1, 1, 2), List(1, 2, 2), List(1, 1, 3), List(2, 3), List(1, 4), List(5))
    val cards = List('2', '3', '4', '5', '6', '7', '8', '9', 'T', 'J', 'Q', 'K', 'A')
    
    def cardValue(base: Long, a: List[Char], cards: List[Char]): Long =
        a.foldLeft(base)(cards.size * _ + cards.indexOf(_))
    
    def hand(a: List[Char]): List[Int] =
        a.groupMapReduce(s => s)(_ => 1)(_ + _).values.toList.sorted
    
    def power(a: List[Char]): Long =
      cardValue(tiers.indexOf(hand(a)), a, cards)
    
    def power3(a: List[Char]): Long = 
      val x = hand(a.filter(_ != 'J'))
      val t = tiers.lastIndexWhere(x.zipAll(_, 0, 0).forall(_ <= _))
      cardValue(t, a, 'J'::cards)
    
    def win(a: List[String], pow: List[Char] => Long) =
        a.flatMap{case s"$hand $bid" => Some((pow(hand.toList), bid.toLong)); case _ => None}
            .sorted.map(_._2).zipWithIndex.map(_ * _.+(1)).sum
    
    def task1(a: List[String]): Long = win(a, power)
    def task2(a: List[String]): Long = win(a, power3)
    
  • purplemonkeymad@programming.dev
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    1 year ago

    This wasn’t too bad. Had a worried moment when the part 2 solution took more than half a second. Maybe a better solution that brute forcing all the joker combinations, but it worked.

    Python
    import re
    import argparse
    import itertools
    from enum import Enum
    
    rule_jokers_enabled = False
    
    class CardType(Enum):
        HighCard = 1
        OnePair = 2
        TwoPair = 3
        ThreeOfAKind = 4
        FullHouse = 5
        FourOfAKind = 6
        FiveOfAKind = 7
    
    class Hand:
        def __init__(self,cards:str,bid:int) -> None:
            self.cards = cards
            self.bid = int(bid)
            if rule_jokers_enabled:
                self.type = self._find_type_joker(cards)
            else:
                self.type = self._find_type(cards)
    
        def _find_type(self,cards:str) -> CardType:
            # group cards based on card counts
            card_list = [*cards]
            card_list.sort()
            grouping = itertools.groupby(card_list,lambda x:x)
            lengths = [len(list(x[1])) for x in grouping]
            if 5 in lengths:
                return CardType.FiveOfAKind
            if 4 in lengths:
                return CardType.FourOfAKind
            if 3 in lengths and 2 in lengths:
                return CardType.FullHouse
            if 3 in lengths:
                return CardType.ThreeOfAKind
            if len([x for x in lengths if x == 2]) == 2:
                return CardType.TwoPair
            if 2 in lengths:
                return CardType.OnePair
            return CardType.HighCard
        
        def _find_type_joker(self,cards:str) -> CardType:
            try:
                joker_i = cards.index("J") 
            except ValueError:
                return self._find_type(cards)
            
            current_value = CardType.HighCard
            for new_card in [*(valid_card_list())]:
                if new_card == "J":
                    continue
                test_cards = list(cards)
                test_cards[joker_i] = new_card
                new_value = self._find_type_joker("".join(test_cards))
                if new_value.value > current_value.value:
                    current_value = new_value
            
            return current_value
    
        
        def sort_string(self):
            v = str(self.type.value) + ":" + "".join(["abcdefghijklmnoZ"[card_value(x)] for x in [*self.cards]])
            return v
        
        def __repr__(self) -> str:
            return f""
    
    
    
    def valid_card_list() -> str:
        if rule_jokers_enabled:
            return "J23456789TQKA"
        return "23456789TJQKA"
    
    def card_value(char:chr):
        return valid_card_list().index(char)
    
    def main(line_list: list):
        hand_list = list()
        for l in line_list:
            card,bid = re.split(' +',l)
            hand = Hand(card,bid)
            hand_list.append(hand)
            #print(hand.sort_string())
        
        hand_list.sort(key=lambda x: x.sort_string())
        print(hand_list)
    
        rank_total = 0
        rank = 1
        for single_hand in hand_list:
            rank_total += rank * single_hand.bid
            rank += 1
        
        print(f"total {rank_total}")
    
    if __name__ == "__main__":
        parser = argparse.ArgumentParser(description="day 1 solver")
        parser.add_argument("-input",type=str)
        parser.add_argument("-part",type=int)
        args = parser.parse_args()
    
        if args.part == 2:
            rule_jokers_enabled = True
    
        filename = args.input
        if filename == None:
            parser.print_help()
            exit(1)
        file = open(filename,'r')
        main([line.rstrip('\n') for line in file.readlines()])
        file.close()
    
    • SteveDinn@lemmy.ca
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      1 year ago

      I barely registered a difference between part 1 and part 2.

      Part 1: 00:00:00.0018302
      Part 2: 00:00:00.0073136
      

      I suppose it took about 3.5 times as long, but I didn’t notice :P

      Edit: I realize that I made the implicit assumption in my solution that it doesn’t make sense to have multiple jokers be interpreted as different values. i.e., The hand with the maximum value will have all Jokers interpreted as the same other card. I think that is true though. It worked out for me anyway.

      • purplemonkeymad@programming.dev
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        1 year ago

        Yea I was thinking there might be a simplification trick, but also figured “there can’t be that many combinations right?” I suspect that was probably an intended optimisation.

    • Faresh@lemmy.ml
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      1 year ago

      I think one doesn’t need to generate all combinations. All combinations using cards already present in the hand should be enough (since a joker can only increase the value of the hand by being grouped with existing cards (since in this game having four of a kind is always better than having any hand with a four of a kind/full house and having 3 is always better than any hand with pairs, and having a pair is better than any card without any cards of the same kind)). This massively decreases the amount of combinations needed to be generated per jokery hand.

  • vole@lemmy.world
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    1 year ago

    Raku

    My hand-type strength calculations could probably be trimmed down a bit. I didn’t hit any big issues today.

    View code on github

    Code (note: doesn't currently display correctly on Lemmy website)
    use v6;
    
    sub MAIN($input) {
        my $file = open $input;
    
        grammar CamelCards {
            token TOP { +%"\n" "\n"*}
            token row {  " "  }
            token hand { \S+ }
            token bid { \d+ }
        }
    
        my $camel-cards = CamelCards.parse($file.slurp);
        my @rows = $camel-cards.map({ (..Str, ..Int) });
        my @ranked-rows1 = @rows.sort({hand-strength($_[0], &hand-type-strength1, '23456789TJQKA'.comb)});
        my $part-one-solution = (@ranked-rows1»[1] Z* 1..*).sum;
        say "part 1: $part-one-solution";
    
        my @ranked-rows2 = @rows.sort({hand-strength($_[0], &hand-type-strength2, 'J23456789TQKA'.comb)});
        my $part-two-solution = (@ranked-rows2»[1] Z* 1..*).sum;
        say "part 2: $part-two-solution";
    }
    
    sub hand-strength($hand, &hand-type-strength, @card-strengths) {
        my $strength = &hand-type-strength($hand);
        for $hand.comb -> $card {
            $strength = $strength +< 8 + @card-strengths.first({ $_ eq $card }, :k);
        }
        return $strength;
    }
    
    sub hand-type-strength1($hand) {
        my @sorted = $hand.comb.sort;
        my @runs = [1];
        my $card = @sorted[0];
        for @sorted[1..*] -> $new-card {
            if $new-card eq $card {
                @runs.tail += 1;
            } else {
                @runs.push(1);
                $card = $new-card;
            }
        }
        return do given @runs.sort {
            when .[0] == 5 { 6 } # Five of a kind
            when .[1] == 4 { 5 } # Four of a kind
            when .[1] == 3 { 4 } # Full House
            when .[2] == 3 { 3 } # Three of a kind
            when .[1] == 2 { 2 } # Two pair
            when .[3] == 2 { 1 } # One pair
            default { 0 } # High card
        };
    }
    
    sub hand-type-strength2($hand) {
        my @sorted = $hand.comb.grep(none /J/).sort;
        if @sorted.elems == 0 {
            return 6;
        } else {
            my @runs = [1];
            my $card = @sorted[0];
            for @sorted[1..*] -> $new-card {
                if $new-card eq $card {
                    @runs.tail += 1;
                } else {
                    @runs.push(1);
                    $card = $new-card;
                }
            }
            @runs.=sort;
            @runs.tail += 5 - @sorted.elems;
            return do given @runs {
                when .[0] == 5 { 6 } # Five of a kind
                when .[1] == 4 { 5 } # Four of a kind
                when .[1] == 3 { 4 } # Full House
                when .[2] == 3 { 3 } # Three of a kind
                when .[1] == 2 { 2 } # Two pair
                when .[3] == 2 { 1 } # One pair
                default { 0 } # High card
            };
        }
    }
    
  • Gobbel2000@feddit.de
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    1 year ago

    Rust

    Getting the count of each card, the two highest counts easily show what type of hand we have. For part 2 I just added the number of jokers to the highest count.

    I spent some time messing around with generics to minimize code duplication between the solutions to both parts. I could have absolutely just copied everything and made small changes, but now my solution is generic over puzzle parts.

  • morrowind@lemmy.ml
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    1 year ago

    Crystal

    got stuck on both parts due to silly mistakes.
    On the other hand I’m no longer behind!

    code
    input = File.read("input.txt").lines
    rank = {
    	'J' => 1,
    	'2' => 2,
    	'3' => 3,
    	'4' => 4,
    	'5' => 5,
    	'6' => 6,
    	'7' => 7,
    	'8' => 8,	
    	'9' => 9,
    	'T' => 10,
    	# 'J' => 11,
    	'Q' => 12,
    	'K' => 13,
    	'A' => 14
    }
    
    hand = input.map do |line|
    	split = line.split
    	weights = split[0].chars.map {|c| rank[c]}
    	{weights, split[1].to_i}
    end
    
    hand.sort! do |a, b|
    	a_rank = get_rank(a[0], true)
    	b_rank = get_rank(b[0], true)
    	
    	# puts "#{a}-#{a_rank} #{b}-#{b_rank}"
    	next  1 if a_rank > b_rank
    	next -1 if b_rank > a_rank
    
    	val = 0
    	5.times do |i| 
    		val =  1 if a[0][i] > b[0][i]
    		val = -1 if b[0][i] > a[0][i]
    		break unless val == 0
    	end
    	val
    end
    
    sum = 0
    hand.each_with_index do |card, i|
    	sum += card[1]*(i+1)
    end
    puts sum
    
    
    def get_rank(card : Array(Int32), joker = false ) : Float64 | Int32
    	aa = card.uniq
    
    	if joker
    		card = aa.map { |c|
    			combo = card.map {|a| a == 1 ? c : a }
    			{combo, get_rank(combo)}
    		}.max_by {|a| a[1]}[0]
    		aa = card.uniq
    	end
    	
    	rank = 6 - aa.size
    	case rank
    	when 3
    		return 3.5 if card.count(aa[0]) == 3
    		return 3   if card.count(aa[0]) == 2
    		return 3   if card.count(aa[1]) == 2
    		return 3.5
    	when 4
    		return 4 if card.count(aa[0]) == 3 || card.count(aa[0]) == 2
    		return 4.5
    	else 
    		return rank
    	end
    end
    
  • pnutzh4x0r@lemmy.ndlug.org
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    1 year ago

    Language: Python

    This was fun. More enjoyable than I initially thought (though I’ve done card sorting code before).

    Part 1

    This was pretty straightforward: create a histogram of the cards in each hand to determine their type, and if there is a tie-breaker, compare each card pairwise. I use the Counter class from collections to do the counting, and then had a dictionary/table to convert labels to numeric values for comparison. I used a very OOP approach and wrote a magic method for comparing hands and used that with Python’s builtin sort. I even got to use Enum!

    LABELS = {l: v for v, l in enumerate('23456789TJQKA', 2)}
    
    class HandType(IntEnum):
        FIVE_OF_A_KIND  = 6
        FOUR_OF_A_KIND  = 5
        FULL_HOUSE      = 4
        THREE_OF_A_KIND = 3
        TWO_PAIR        = 2
        ONE_PAIR        = 1
        HIGH_CARD       = 0
    
    class Hand:
        def __init__(self, cards=str, bid=str):
            self.cards  = cards
            self.bid    = int(bid)
            counts      = Counter(self.cards)
            self.type   = (
                HandType.FIVE_OF_A_KIND  if len(counts) == 1 else
                HandType.FOUR_OF_A_KIND  if len(counts) == 2 and any(l for l, count in counts.items() if count == 4) else
                HandType.FULL_HOUSE      if len(counts) == 2 and any(l for l, count in counts.items() if count == 3) else
                HandType.THREE_OF_A_KIND if len(counts) == 3 and any(l for l, count in counts.items() if count == 3) else
                HandType.TWO_PAIR        if len(counts) == 3 and any(l for l, count in counts.items() if count == 2) else
                HandType.ONE_PAIR        if len(counts) == 4 and any(l for l, count in counts.items() if count == 2) else
                HandType.HIGH_CARD
            )
    
        def __lt__(self, other):
            if self.type == other.type:
                for s_label, o_label in zip(self.cards, other.cards):
                    if LABELS[s_label] == LABELS[o_label]:
                        continue
                    return LABELS[s_label] < LABELS[o_label]
                return False
            return self.type < other.type
    
        def __repr__(self):
            return f'Hand(cards={self.cards},bid={self.bid},type={self.type})'
    
    def read_hands(stream=sys.stdin) -> list[Hand]:
        return [Hand(*line.split()) for line in stream]
    
    def main(stream=sys.stdin) -> None:
        hands    = sorted(read_hands(stream))
        winnings = sum(rank * hand.bid for rank, hand in enumerate(hands, 1))
        print(winnings)
    
    Part 2

    For the second part, I just had to add some post-processing code to convert the jokers into actual cards. The key insight is to find the highest and most numerous non-Joker card and convert all the Jokers to that card label.

    This had two edge cases that tripped me up:

    1. ‘JJJJJ’: There is no other non-Joker here, so I messed up and ranked this the lowest because I ended up removing all counts.

    2. ‘JJJ12’: This also messed me up b/c the Joker was the most numerous card, and I didn’t handle that properly.

    Once I fixed the post-processing code though, everything else remained the same. Below, I only show the parts that changed from Part A.

    LABELS = {l: v for v, l in enumerate('J23456789TQKA', 1)}
    
    ...
    
    class Hand:
        def __init__(self, cards=str, bid=str):
            self.cards  = cards
            self.bid    = int(bid)
            counts      = Counter(self.cards)
    
            if 'J' in counts and len(counts) > 1:
                max_label = max(set(counts) - {'J'}, key=lambda l: (counts[l], LABELS[l]))
                counts[max_label] += counts['J']
                del counts['J']
    
            self.type   = (...)
    

    GitHub Repo

  • Nighed@sffa.community
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    1 year ago

    C#

    Not too bad - I just scored every hand for the first part so I could easily sort it.

    For the second part I just brute forced the replacements for the hand type matchinge (first digit of score)

    Task1

    public class Day7Task1:IRunnable {

    public static Dictionary CardValues = new Dictionary()
     {
         { '2', "01" },
         { '3', "02" },
         { '4', "03" },
         { '5', "04" },
         { '6', "05" },
         { '7', "06" },
         { '8', "07" },
         { '9', "08" },
         { 'T', "09" },
         { 'J', "10" },
         { 'Q', "11" },
         { 'K', "12" },
         { 'A', "13" }
     };
     
     public void Run()
     {
         //var inputLines = File.ReadAllLines("Days/Seven/Day7ExampleInput.txt");
         var inputLines = File.ReadAllLines("Days/Seven/Day7Input.txt");
    
    
    
         var hands = inputLines.Select(line =>
         {
             var split = line.Split(' ', StringSplitOptions.RemoveEmptyEntries | StringSplitOptions.TrimEntries);
             return new Hand(split[0],  split[1] );
         }).ToList();
    
         var sortedHands = hands.OrderBy(hand => hand.Score).ToList();
    
         long resultValue = 0;
    
         for (int i = 1; i < hands.Count()+1; i++)
         {
             resultValue += i * sortedHands[i-1].Bid;
         }
    
         Console.WriteLine("Result:" + resultValue);
    
     }
    
     public class Hand
     {
         public Hand(string cards, string bid)
         {
             Cards = cards;
             Bid = int.Parse(bid);
             Score = GenerateScore();
         }
    
         public string Cards { get; set; }
         public int Bid { get; set; }
         
         public long Score { get; }
    
         private long GenerateScore()
         {
             var resultString = new StringBuilder();
             var cardGroups = Cards.GroupBy(c => c).ToList();
             var groupCounts = cardGroups.OrderByDescending(g => g.Count()).Select(g => g.Count()).ToList();
             if (cardGroups.Count() == 1)
             {
                 resultString.Append("7");
             }
             else if(cardGroups.Count() == 2 && (cardGroups[0].Count() == 4 || cardGroups[0].Count() == 1))
             {
                 resultString.Append("6");
             }
             else if(cardGroups.Count() == 2 && (cardGroups[0].Count() == 3 || cardGroups[0].Count() == 2))
             {
                 resultString.Append("5");
             }
             else if(cardGroups.Count() == 3 && (cardGroups[0].Count() == 3 || cardGroups[1].Count() == 3 || cardGroups[2].Count() == 3))
             {
                 resultString.Append("4");
             }
             else if(cardGroups.Count() == 3 && groupCounts[0] == 2 && groupCounts[1] == 2 && groupCounts[2] == 1)
             {
                 resultString.Append("3");
             }
             else if(cardGroups.Count() == 4 )
             {
                 resultString.Append("2");
             }
             else
             {
                 resultString.Append("1");
             }
    
             foreach (var card in Cards)
             {
                 resultString.Append(Day7Task1.CardValues[card]);
             }
    
             Console.WriteLine("Cards:{0} Score:{1}",Cards,resultString);
             return long.Parse(resultString.ToString());
         }
     }
    }
    
    Task2
    public class Day7Task2:IRunnable
    {
        public static Dictionary CardValues = new Dictionary()
        {
            { '2', "01" },
            { '3', "02" },
            { '4', "03" },
            { '5', "04" },
            { '6', "05" },
            { '7', "06" },
            { '8', "07" },
            { '9', "08" },
            { 'T', "09" },
            { 'J', "00" },
            { 'Q', "11" },
            { 'K', "12" },
            { 'A', "13" }
        };
        
        public void Run()
        {
            //var inputLines = File.ReadAllLines("Days/Seven/Day7ExampleInput.txt");
            var inputLines = File.ReadAllLines("Days/Seven/Day7Input.txt");
    
    
    
            var hands = inputLines.Select(line =>
            {
                var split = line.Split(' ', StringSplitOptions.RemoveEmptyEntries | StringSplitOptions.TrimEntries);
                return new Hand(split[0],  split[1] );
            }).ToList();
    
            var sortedHands = hands.OrderBy(hand => hand.Score).ToList();
    
            long resultValue = 0;
    
            for (int i = 1; i < hands.Count()+1; i++)
            {
                resultValue += i * sortedHands[i-1].Bid;
            }
    
            Console.WriteLine("Result:" + resultValue);
    
        }
    
        public class Hand
        {
            public Hand(string cards, string bid)
            {
                Cards = cards;
                Bid = int.Parse(bid);
                Score = GenerateScore();
            }
    
            public string Cards { get; set; }
            public int Bid { get; set; }
            
            public long Score { get; }
    
            private long GenerateScore()
            {
                var generateFirstDigit = new Func(cards =>
                {
                    var cardGroups = cards.GroupBy(c => c).ToList();
                    var groupCounts = cardGroups.OrderByDescending(g => g.Count()).Select(g => g.Count()).ToList();
                    if (cardGroups.Count() == 1)
                    {
                        return 7;
                    }
                    else if (cardGroups.Count() == 2 && (cardGroups[0].Count() == 4 || cardGroups[0].Count() == 1))
                    {
                        return 6;
                    }
                    else if (cardGroups.Count() == 2 && (cardGroups[0].Count() == 3 || cardGroups[0].Count() == 2))
                    {
                        return 5;
                    }
                    else if (cardGroups.Count() == 3 && (cardGroups[0].Count() == 3 || cardGroups[1].Count() == 3 || cardGroups[2].Count() == 3))
                    {
                        return 4;
                    }
                    else if (cardGroups.Count() == 3 && groupCounts[0] == 2 && groupCounts[1] == 2 && groupCounts[2] == 1)
                    {
                        return 3;
                    }
                    else if (cardGroups.Count() == 4)
                    {
                        return 2;
                    }
                    else
                    {
                        return 1;
                    }
                });
                
                var resultString = new StringBuilder();
    
                var maxFistDigit = Day7Task2.CardValues.Keys.Select(card => generateFirstDigit(Cards.Replace('J', card))).Max();
    
                resultString.Append(maxFistDigit);
                
                foreach (var card in Cards)
                {
                    resultString.Append(Day7Task2.CardValues[card]);
                }
    
                Console.WriteLine("Cards:{0} Score:{1}",Cards,resultString);
                return long.Parse(resultString.ToString());
            }
        }
    }
    
  • porotoman99@lemmy.world
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    1 year ago

    Python

    Part 1: https://github.com/porotoman99/Advent-of-Code-2023/blob/main/Day 7/part1.py

    Code
    import os
    
    filePath = os.path.dirname(os.path.realpath(__file__))
    inputFilePath = filePath + "\\adventofcode.com_2023_day_7_input.txt"
    # inputFilePath = filePath + "\\part1.txt"
    
    def typeSort(hand):
    	cardCount = {
    		"2": 0,
    		"3": 0,
    		"4": 0,
    		"5": 0,
    		"6": 0,
    		"7": 0,
    		"8": 0,
    		"9": 0,
    		"T": 0,
    		"J": 0,
    		"Q": 0,
    		"K": 0,
    		"A": 0
    	}
    	for card in hand:
    		cardCount[card] += 1
    	cardTotals = list(cardCount.values())
    	cardTotals.sort(reverse=True)
    	if(cardTotals[0] == 5):
    		return 6
    	elif(cardTotals[0] == 4):
    		return 5
    	elif(cardTotals[0] == 3 and cardTotals[1] == 2):
    		return 4
    	elif(cardTotals[0] == 3):
    		return 3
    	elif(cardTotals[0] == 2 and cardTotals[1] == 2):
    		return 2
    	elif(cardTotals[0] == 2):
    		return 1
    	else:
    		return 0
    
    def bucketSort(camelCard):
    	totalScore = 0
    	cardOrder = ["2","3","4","5","6","7","8","9","T","J","Q","K","A"]
    	hand = camelCard[0]
    	totalScore += cardOrder.index(hand[4]) * 15 ** 1
    	totalScore += cardOrder.index(hand[3]) * 15 ** 2
    	totalScore += cardOrder.index(hand[2]) * 15 ** 3
    	totalScore += cardOrder.index(hand[1]) * 15 ** 4
    	totalScore += cardOrder.index(hand[0]) * 15 ** 5
    	return totalScore
    
    hands = []
    bids = []
    
    with open(inputFilePath) as inputFile:
    	for line in inputFile:
    		lineSplit = line.split()
    		hand = lineSplit[0]
    		bid = lineSplit[1]
    		hands.append(hand)
    		bids.append(bid)
    
    bids = [int(bid) for bid in bids]
    
    camelCards = list(zip(hands,bids))
    
    typeBuckets = [[],[],[],[],[],[],[]]
    
    for camelCard in camelCards:
    	hand = camelCard[0]
    	typeScore = typeSort(hand)
    	typeBuckets[typeScore].append(camelCard)
    
    finalCardSort = []
    
    for bucket in typeBuckets:
    	if(len(bucket) > 1):
    		bucket.sort(key=bucketSort)
    	for camelCard in bucket:
    		finalCardSort.append(camelCard)
    
    camelScores = []
    
    for camelIndex in range(len(finalCardSort)):
    	scoreMultiplier = camelIndex + 1
    	camelCard = finalCardSort[camelIndex]
    	camelScores.append(camelCard[1] * scoreMultiplier)
    
    print(sum(camelScores))
    

    Part 2: https://github.com/porotoman99/Advent-of-Code-2023/blob/main/Day 7/part2.py

    Code
    import os
    
    filePath = os.path.dirname(os.path.realpath(__file__))
    inputFilePath = filePath + "\\adventofcode.com_2023_day_7_input.txt"
    # inputFilePath = filePath + "\\part1.txt"
    
    def typeSort(hand):
    	cardCount = {
    		"J": 0,
    		"2": 0,
    		"3": 0,
    		"4": 0,
    		"5": 0,
    		"6": 0,
    		"7": 0,
    		"8": 0,
    		"9": 0,
    		"T": 0,
    		"Q": 0,
    		"K": 0,
    		"A": 0
    	}
    	for card in hand:
    		cardCount[card] += 1
    	jokerCount = cardCount["J"]
    	cardCount["J"] = 0
    	cardTotals = list(cardCount.values())
    	cardTotals.sort(reverse=True)
    	if(cardTotals[0] + jokerCount == 5):
    		return 6
    	elif(cardTotals[0] + jokerCount == 4):
    		return 5
    	elif(
    		cardTotals[0] + jokerCount == 3 and cardTotals[1] == 2
    		or cardTotals[0] == 3 and cardTotals[1] + jokerCount == 2
    	):
    		return 4
    	elif(cardTotals[0] + jokerCount == 3):
    		return 3
    	elif(
    		cardTotals[0] + jokerCount == 2 and cardTotals[1] == 2
    		or cardTotals[0] == 2 and cardTotals[1] + jokerCount == 2
    	):
    		return 2
    	elif(cardTotals[0] + jokerCount == 2):
    		return 1
    	else:
    		return 0
    
    def bucketSort(camelCard):
    	totalScore = 0
    	cardOrder = ["J","2","3","4","5","6","7","8","9","T","Q","K","A"]
    	hand = camelCard[0]
    	totalScore += cardOrder.index(hand[4]) * 15 ** 1
    	totalScore += cardOrder.index(hand[3]) * 15 ** 2
    	totalScore += cardOrder.index(hand[2]) * 15 ** 3
    	totalScore += cardOrder.index(hand[1]) * 15 ** 4
    	totalScore += cardOrder.index(hand[0]) * 15 ** 5
    	return totalScore
    
    hands = []
    bids = []
    
    with open(inputFilePath) as inputFile:
    	for line in inputFile:
    		lineSplit = line.split()
    		hand = lineSplit[0]
    		bid = lineSplit[1]
    		hands.append(hand)
    		bids.append(bid)
    
    bids = [int(bid) for bid in bids]
    
    camelCards = list(zip(hands,bids))
    
    typeBuckets = [[],[],[],[],[],[],[]]
    
    for camelCard in camelCards:
    	hand = camelCard[0]
    	typeScore = typeSort(hand)
    	typeBuckets[typeScore].append(camelCard)
    
    finalCardSort = []
    
    for bucket in typeBuckets:
    	if(len(bucket) > 1):
    		bucket.sort(key=bucketSort)
    	for camelCard in bucket:
    		finalCardSort.append(camelCard)
    
    camelScores = []
    
    for camelIndex in range(len(finalCardSort)):
    	scoreMultiplier = camelIndex + 1
    	camelCard = finalCardSort[camelIndex]
    	camelScores.append(camelCard[1] * scoreMultiplier)
    
    print(sum(camelScores))
    

    I tried to do this one as quickly as possible, so the code is more messy than I would prefer, but it works, and I don’t think the solution is too bad overall.

    Edit: I went back and changed it to be a bit better. Here are my new solutions:

    Part 1 v2: https://github.com/porotoman99/Advent-of-Code-2023/blob/main/Day 7/part1v2.py

    Code
    import os
    
    filePath = os.path.dirname(os.path.realpath(__file__))
    inputFilePath = filePath + "\\adventofcode.com_2023_day_7_input.txt"
    # inputFilePath = filePath + "\\part1.txt"
    
    CARD_ORDER = "23456789TJQKA"
    
    def typeSort(camelCard):
    	cardCount = {}
    	for card in CARD_ORDER:
    		cardCount[card] = 0
    	hand = camelCard[0]
    	for card in hand:
    		cardCount[card] += 1
    	cardTotals = list(cardCount.values())
    	cardTotals.sort(reverse=True)
    	if(cardTotals[0] == 5):
    		return 6
    	elif(cardTotals[0] == 4):
    		return 5
    	elif(cardTotals[0] == 3 and cardTotals[1] == 2):
    		return 4
    	elif(cardTotals[0] == 3):
    		return 3
    	elif(cardTotals[0] == 2 and cardTotals[1] == 2):
    		return 2
    	elif(cardTotals[0] == 2):
    		return 1
    	else:
    		return 0
    
    def handSort(camelCard):
    	totalScore = 0
    	hand = camelCard[0]
    	totalScore += CARD_ORDER.index(hand[4]) * 15 ** 1
    	totalScore += CARD_ORDER.index(hand[3]) * 15 ** 2
    	totalScore += CARD_ORDER.index(hand[2]) * 15 ** 3
    	totalScore += CARD_ORDER.index(hand[1]) * 15 ** 4
    	totalScore += CARD_ORDER.index(hand[0]) * 15 ** 5
    	return totalScore
    
    hands = []
    bids = []
    
    with open(inputFilePath) as inputFile:
    	for line in inputFile:
    		lineSplit = line.split()
    		hand = lineSplit[0]
    		bid = lineSplit[1]
    		hands.append(hand)
    		bids.append(int(bid))
    
    camelCards = list(zip(hands,bids))
    camelCards = sorted(camelCards, key=lambda x: (typeSort(x), handSort(x)))
    
    camelScores = []
    
    for camelIndex in range(len(camelCards)):
    	scoreMultiplier = camelIndex + 1
    	camelCard = camelCards[camelIndex]
    	camelScores.append(camelCard[1] * scoreMultiplier)
    
    print(sum(camelScores))
    

    Part 2 v2: https://github.com/porotoman99/Advent-of-Code-2023/blob/main/Day 7/part2v2.py

    Code
    import os
    
    filePath = os.path.dirname(os.path.realpath(__file__))
    inputFilePath = filePath + "\\adventofcode.com_2023_day_7_input.txt"
    # inputFilePath = filePath + "\\part1.txt"
    
    CARD_ORDER = "J23456789TQKA"
    
    def typeSort(camelCard):
    	cardCount = {}
    	for card in CARD_ORDER:
    		cardCount[card] = 0
    	hand = camelCard[0]
    	for card in hand:
    		cardCount[card] += 1
    	jokerCount = cardCount["J"]
    	cardCount["J"] = 0
    	cardTotals = list(cardCount.values())
    	cardTotals.sort(reverse=True)
    	if(cardTotals[0] + jokerCount == 5):
    		return 6
    	elif(cardTotals[0] + jokerCount == 4):
    		return 5
    	elif(
    		cardTotals[0] + jokerCount == 3 and cardTotals[1] == 2
    		or cardTotals[0] == 3 and cardTotals[1] + jokerCount == 2
    	):
    		return 4
    	elif(cardTotals[0] + jokerCount == 3):
    		return 3
    	elif(
    		cardTotals[0] + jokerCount == 2 and cardTotals[1] == 2
    		or cardTotals[0] == 2 and cardTotals[1] + jokerCount == 2
    	):
    		return 2
    	elif(cardTotals[0] + jokerCount == 2):
    		return 1
    	else:
    		return 0
    
    def handSort(camelCard):
    	totalScore = 0
    	hand = camelCard[0]
    	totalScore += CARD_ORDER.index(hand[4]) * 15 ** 1
    	totalScore += CARD_ORDER.index(hand[3]) * 15 ** 2
    	totalScore += CARD_ORDER.index(hand[2]) * 15 ** 3
    	totalScore += CARD_ORDER.index(hand[1]) * 15 ** 4
    	totalScore += CARD_ORDER.index(hand[0]) * 15 ** 5
    	return totalScore
    
    hands = []
    bids = []
    
    with open(inputFilePath) as inputFile:
    	for line in inputFile:
    		lineSplit = line.split()
    		hand = lineSplit[0]
    		bid = lineSplit[1]
    		hands.append(hand)
    		bids.append(int(bid))
    
    camelCards = list(zip(hands,bids))
    camelCards = sorted(camelCards, key=lambda x: (typeSort(x), handSort(x)))
    
    camelScores = []
    
    for camelIndex in range(len(camelCards)):
    	scoreMultiplier = camelIndex + 1
    	camelCard = camelCards[camelIndex]
    	camelScores.append(camelCard[1] * scoreMultiplier)
    
    print(sum(camelScores))
    
  • soulsource@discuss.tchncs.de
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    1 year ago

    [language: Lean4]

    As with the previous days: I’ll only post the solution and parsing, not the dependencies I’ve put into separate files. For the full source code, please see github.

    The key idea for part 2 was that

    Spoiler

    it doesn’t make any sense to pick different cards for the jokers, and that it’s always the highest score to assign all jokers to the most frequent card.

    Solution
    inductive Card
      | two
      | three
      | four
      | five
      | six
      | seven
      | eight
      | nine
      | ten
      | jack
      | queen
      | king
      | ace
      deriving Repr, Ord, BEq
    
    inductive Hand
      | mk : Card → Card → Card → Card → Card → Hand
      deriving Repr, BEq
    
    private inductive Score
      | highCard
      | onePair
      | twoPair
      | threeOfAKind
      | fullHouse
      | fourOfAKind
      | fiveOfAKind
      deriving Repr, Ord, BEq
    
    -- we need countCards in part 2 again, but there it has different types
    private class CardList (η : Type) (χ : outParam Type) where
      cardList : η → List χ
    
    -- similarly, we can implement Ord in terms of CardList and Score
    private class Scorable (η : Type) where
      score : η → Score
    
    private instance : CardList Hand Card where
      cardList := λ
        | .mk a b c d e => [a,b,c,d,e]
    
    private def countCards {η χ : Type} (input :η) [CardList η χ] [Ord χ] [BEq χ] : List (Nat × χ) :=
      let ordered := (CardList.cardList input).quicksort
      let helper := λ (a : List (Nat × χ)) (c : χ) ↦ match a with
      | [] => [(1, c)]
      | a :: as =>
        if a.snd == c then
          (a.fst + 1, c) :: as
        else
          (1, c) :: a :: as
      List.quicksortBy (·.fst > ·.fst) $ ordered.foldl helper []
    
    private def evaluateCountedCards : (l : List (Nat × α)) → Score
      | [_] => Score.fiveOfAKind -- only one entry means all cards are equal
      | (4,_) :: _ => Score.fourOfAKind
      | [(3,_), (2,_)] => Score.fullHouse
      | (3,_) :: _ => Score.threeOfAKind
      | [(2,_), (2,_), _] => Score.twoPair
      | (2,_) :: _ => Score.onePair
      | _ => Score.highCard
    
    private def Hand.score (hand : Hand) : Score :=
      evaluateCountedCards $ countCards hand
    
    private instance : Scorable Hand where
      score := Hand.score
    
    instance {σ χ : Type} [Scorable σ] [CardList σ χ] [Ord χ] : Ord σ where
      compare (a b : σ) :=
        let comparedScores := Ord.compare (Scorable.score a) (Scorable.score b)
        if comparedScores != Ordering.eq then
          comparedScores
        else
          Ord.compare (CardList.cardList a) (CardList.cardList b)
    
    private def Card.fromChar? : Char → Option Card
    | '2' => some Card.two
    | '3' => some Card.three
    | '4' => some Card.four
    | '5' => some Card.five
    | '6' => some Card.six
    | '7' => some Card.seven
    | '8' => some Card.eight
    | '9' => some Card.nine
    | 'T' => some Card.ten
    | 'J' => some Card.jack
    | 'Q' => some Card.queen
    | 'K' => some Card.king
    | 'A' => some Card.ace
    | _ => none
    
    private def Hand.fromString? (input : String) : Option Hand :=
      match input.toList.mapM Card.fromChar? with
      | some [a, b, c, d, e] => Hand.mk a b c d e
      | _ => none
    
    abbrev Bet := Nat
    
    structure Player where
      hand : Hand
      bet : Bet
      deriving Repr
    
    def parse (input : String) : Except String (List Player) := do
      let lines := input.splitOn "\n" |> List.map String.trim |> List.filter String.notEmpty
      let parseLine := λ (line : String) ↦
        if let [hand, bid] := line.split Char.isWhitespace |> List.map String.trim |> List.filter String.notEmpty then
          Option.zip (Hand.fromString? hand) (String.toNat? bid)
          |> Option.map (uncurry Player.mk)
          |> Option.toExcept s!"Line could not be parsed: {line}"
        else
          throw s!"Failed to parse. Line did not separate into hand and bid properly: {line}"
      lines.mapM parseLine
    
    def part1 (players : List Player) : Nat :=
      players.quicksortBy (λ p q ↦ p.hand < q.hand)
      |> List.enumFrom 1
      |> List.foldl (λ r p ↦ p.fst * p.snd.bet + r) 0
    
    
    ------------------------------------------------------------------------------------------------------
    -- Again a riddle where part 2 needs different data representation, why are you doing this to me? Why?
    -- (Though, strictly speaking, I could just add "joker" to the list of cards in part 1 and treat it special)
    
    private inductive Card2
      | joker
      | two
      | three
      | four
      | five
      | six
      | seven
      | eight
      | nine
      | ten
      | queen
      | king
      | ace
      deriving Repr, Ord, BEq
    
    private def Card.toCard2 : Card → Card2
      | .two => Card2.two
      | .three => Card2.three
      | .four => Card2.four
      | .five => Card2.five
      | .six => Card2.six
      | .seven => Card2.seven
      | .eight => Card2.eight
      | .nine => Card2.nine
      | .ten => Card2.ten
      | .jack => Card2.joker
      | .queen => Card2.queen
      | .king => Card2.king
      | .ace => Card2.ace
    
    private inductive Hand2
      | mk : Card2 → Card2 → Card2 → Card2 → Card2 → Hand2
      deriving Repr
    
    private def Hand.toHand2 : Hand → Hand2
      | Hand.mk a b c d e => Hand2.mk a.toCard2 b.toCard2 c.toCard2 d.toCard2 e.toCard2
    
    instance : CardList Hand2 Card2 where
      cardList := λ
        | .mk a b c d e => [a,b,c,d,e]
    
    private def Hand2.score (hand : Hand2) : Score :=
      -- I could be dumb here and just let jokers be any other card, but that would be really wasteful
      -- Also, I'm pretty sure there is no combination that would benefit from jokers being mapped to
      -- different cards.
      -- and, even more important, I think we can always map jokers to the most frequent card and are
      -- still correct.
      let counted := countCards hand
      let (jokers, others) := counted.partition λ e ↦ e.snd == Card2.joker
      let jokersReplaced := match jokers, others with
      | (jokers, _) :: _ , (a, ac) :: as => (a+jokers, ac) :: as
      | _ :: _, [] => jokers
      | [], others => others
      evaluateCountedCards jokersReplaced
    
    private instance : Scorable Hand2 where
      score := Hand2.score
    
    private structure Player2 where
      bet : Bet
      hand2 : Hand2
    
    def part2 (players : List Player) : Nat :=
      let players := players.map λ p ↦
        {bet := p.bet, hand2 := p.hand.toHand2 : Player2}
      players.quicksortBy (λ p q ↦ p.hand2 < q.hand2)
      |> List.enumFrom 1
      |> List.foldl (λ r p ↦ p.fst * p.snd.bet + r) 0
    
  • snowe@programming.dev
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    1 year ago

    Ruby

    !ruby@programming.dev

    https://github.com/snowe2010/advent-of-code/blob/master/ruby_aoc/2023/day07/day07.rb

    Gonna clean it up now, but pretty simple at the end of it all. Helps that ruby has several methods to make this dead simple, like tally, any?, all?, and zip


    Cleaned up solution:

    def get_score(tally)
      vals = tally.values
      map = {
        ->(x) { x.any?(5) } => 7,
        ->(x) { x.any?(4) } => 6,
        ->(x) { x.any?(3) && x.any?(2) } => 5,
        ->(x) { x.any?(3) && tally.all? { |_, v| v != 2 } } => 4,
        ->(x) { x.count(2) == 2 } => 3,
        ->(x) { x.one?(2) && tally.all? { |_, v| v <= 2 } } => 2,
        ->(x) { x.all?(1) } => 1,
      }
      map.find { |lambda, _| lambda.call(vals) }[1]
    end
    
    def get_ranking(lines, score_map, scores)
      lines.zip(scores).to_h.sort do |a, b|
        a_line, a_score = a
        b_line, b_score = b
        if a_score == b_score
          a_hand, _ = a_line.split
          b_hand, _ = b_line.split
          diff = a_hand.chars.zip(b_hand.chars).drop_while { |a, b| a == b }[0]
          card_1 = score_map.index(diff[0])
          card_2 = score_map.index(diff[1])
          card_1 <=> card_2
        else
          a_score <=> b_score
        end
      end
    end
    
    def calculate_total_winnings(ranking)
      max_rank = ranking.size
      (1..max_rank).sum(0) do |rank|
        line = ranking[rank - 1]
        _, bid = line[0].split
        bid.to_i * rank
      end
    end
    
    score_map_p1 = %w[. . 2 3 4 5 6 7 8 9 T J Q K A]
    score_map_p2 = %w[. . J 2 3 4 5 6 7 8 9 T Q K A]
    
    execute(1) do |lines|
      scores = lines.map do |line|
        hand, _ = line.split
        tally = hand.split('').tally
        get_score tally
      end
      ranking = get_ranking(lines, score_map_p1, scores)
      calculate_total_winnings ranking
    end
    
    execute(2) do |lines|
      scores = lines.map do |line|
        hand, _ = line.split
        hand_split = hand.split('')
        tally = hand_split.tally
        if hand_split.any? { |c| c == 'J' }
          highest_non_j = tally.reject { |k, v| k == 'J' }.max_by { |k, v| v }
          if highest_non_j.nil?
            tally = { 'A': 5 }
          else
            tally[highest_non_j[0]] += tally['J']
          end
          tally.delete('J')
        end
        get_score tally
      end
      ranking = get_ranking(lines, score_map_p2, scores)
      calculate_total_winnings(ranking)
    end
    
  • Andy@programming.dev
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    edit-2
    1 year ago

    Factor on github (with comments and imports):

    ! hand: "A23A4"
    ! card: 'Q'
    ! hand-bid: { "A23A4" 220 }
    
    : card-key ( ch -- n ) "23456789TJQKA" index ;
    
    : five-kind?  ( hand -- ? ) cardinality 1 = ;
    : four-kind?  ( hand -- ? ) sorted-histogram last last 4 = ;
    : full-house? ( hand -- ? ) sorted-histogram { [ last last 3 = ] [ length 2 = ] } && ;
    : three-kind? ( hand -- ? ) sorted-histogram { [ last last 3 = ] [ length 3 = ] } && ;
    : two-pair?   ( hand -- ? ) sorted-histogram { [ last last 2 = ] [ length 3 = ] } && ;
    : one-pair?   ( hand -- ? ) sorted-histogram { [ last last 2 = ] [ length 4 = ] } && ;
    : high-card?  ( hand -- ? ) cardinality 5 = ;
    
    : type-key ( hand -- n )
      [ 0 ] dip
      { [ high-card? ] [ one-pair? ] [ two-pair? ] [ three-kind? ] [ full-house? ] [ four-kind? ] [ five-kind? ] }
      [ dup empty? ] [
        unclip pick swap call( h -- ? )
        [ drop f ] [ [ 1 + ] 2dip ] if
      ] until 2drop
    ;
    
    :: (hand-compare) ( hand1 hand2 type-key-quot card-key-quot -- <=> )
      hand1 hand2 type-key-quot compare
      dup +eq+ = [
        drop hand1 hand2 [ card-key-quot compare ] { } 2map-as
        { +eq+ } without ?first
        dup [ drop +eq+ ] unless
      ] when
    ; inline
    
    : hand-compare ( hand1 hand2 -- <=> ) [ type-key ] [ card-key ] (hand-compare) ;
    
    : input>hand-bids ( -- hand-bids )
      "vocab:aoc-2023/day07/input.txt" utf8 file-lines
      [ " " split1 string>number 2array ] map
    ;
    
    : solve ( hand-compare-quot -- )
      '[ [ first ] bi@ @ ] input>hand-bids swap sort-with
      [ 1 + swap last * ] map-index sum .
    ; inline
    
    : part1 ( -- ) [ hand-compare ] solve ;
    
    : card-key-wilds ( ch -- n ) "J23456789TQKA" index ;
    
    : type-key-wilds ( hand -- n )
      [ type-key ] [ "J" within length ] bi
      2array {
        { { 0 1 } [ 1 ] }
        { { 1 1 } [ 3 ] } { { 1 2 } [ 3 ] }
        { { 2 1 } [ 4 ] } { { 2 2 } [ 5 ] }
        { { 3 1 } [ 5 ] } { { 3 3 } [ 5 ] }
        { { 4 2 } [ 6 ] } { { 4 3 } [ 6 ] }
        { { 5 1 } [ 6 ] } { { 5 4 } [ 6 ] }
        [ first ]
      } case
    ;
    
    : hand-compare-wilds ( hand1 hand2 -- <=> ) [ type-key-wilds ] [ card-key-wilds ] (hand-compare) ;
    
    : part2 ( -- ) [ hand-compare-wilds ] solve ;